Calculate the mass of oxygen released by the action of water on 10.0 grams of sodium peroxide (the other product is sodium hydroxide).

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asked Oct 9, 2018 52.8k views

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Victor Chekalin · Answer 1 · 2018-10-13T01:18:47+0000

The reaction equation:
2H₂O + 2Na₂O₂ → 4NaOH + O₂

Moles of sodium peroxide = 10 / 78 = 0.128

Moles of oxygen released = 0.128 / 2 = 0.064 mol
Mass of oxygen = 0.064 x 32

Mass of oxygen = 2.05 grams

Calculate the mass of oxygen released by the action of water on 10.0 grams of sodium peroxide (the other product is sodium hydroxide).

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