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Help???????????????????​-example-1
User Unbywyd
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1 Answer

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Answer:

Please check the explanation.

Explanation:

Part a)

Given

  • m∠ABD = (7q - 46)°
  • m∠CBD = (3q + 6)°

It is clear that m∠ABD and m∠CBD lie on a straight line.

Thus, the sum of m∠ABD and m∠CBD will be 180°.

Hence,

m∠ABD and m∠CBD are supplementary angles.

Part b)

As m∠ABD and m∠CBD are supplementary angles, so the sum of m∠ABD and m∠CBD will be 180°.

Thus,

m∠ABD + m∠CBD = 180°

substitute m∠ABD = (7q-46)° and m∠CBD = (3q + 6)°

(7q-46)° + (3q + 6)° = 180°

Part c)

Given the equation

(7q-46)° + (3q + 6)° = 180°

Combining the like terms

7q + 3q - 46 + 6 = 180

10q - 40 = 180

10q = 180 + 40

10q = 220

divide both sides by 10

10q/10 = 220/10

q = 22

Therefore, the value of q = 22

Part d)

As

m∠ABD = (7q-46)°

substituting q = 22

m∠ABD = 7(22) - 46

= 154 - 46

= 108°

also

m∠CBD = (3q + 6)°

substituting q = 22

m∠CBD = 3(22) + 6

= 66+6

= 72°

Therefore,

  • m∠ABD = 108°
  • m∠CBD = 72°
User Addedlovely
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