154k views
14 votes
Help???????????????????​

Help???????????????????​-example-1
User Unbywyd
by
7.5k points

1 Answer

4 votes

Answer:

Please check the explanation.

Explanation:

Part a)

Given

  • m∠ABD = (7q - 46)°
  • m∠CBD = (3q + 6)°

It is clear that m∠ABD and m∠CBD lie on a straight line.

Thus, the sum of m∠ABD and m∠CBD will be 180°.

Hence,

m∠ABD and m∠CBD are supplementary angles.

Part b)

As m∠ABD and m∠CBD are supplementary angles, so the sum of m∠ABD and m∠CBD will be 180°.

Thus,

m∠ABD + m∠CBD = 180°

substitute m∠ABD = (7q-46)° and m∠CBD = (3q + 6)°

(7q-46)° + (3q + 6)° = 180°

Part c)

Given the equation

(7q-46)° + (3q + 6)° = 180°

Combining the like terms

7q + 3q - 46 + 6 = 180

10q - 40 = 180

10q = 180 + 40

10q = 220

divide both sides by 10

10q/10 = 220/10

q = 22

Therefore, the value of q = 22

Part d)

As

m∠ABD = (7q-46)°

substituting q = 22

m∠ABD = 7(22) - 46

= 154 - 46

= 108°

also

m∠CBD = (3q + 6)°

substituting q = 22

m∠CBD = 3(22) + 6

= 66+6

= 72°

Therefore,

  • m∠ABD = 108°
  • m∠CBD = 72°
User Addedlovely
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories