Question

Consider the neutralization reaction between CH3COOH and Sr(OH)2. Complete and balance the neutralization reaction, name the products, and write the net ionic equation.

Answer 1

I believe this would be the solution.

Answer 2

See the explanation.

Step-by-step explanation:

Hello,

In this case, the overall double displacement undergoing chemical reaction turn out into:

`Sr(OH)_2+2CH_3COOH-->(CH_3COO)_2Sr+2H_2O`

The names are:

`Sr(OH)_2`: strontium hydroxide.

`CH_3COOH`: acetic acid.

`(CH_3COO)_2Sr`: strontium acetate.

`H_2O`: water.

Now, the net ionic equation is obtained from the following procedure:

`Sr^(+2)(aq)+OH^-(aq)+CH_3COOH(aq)-->CH_3COO^-(aq)+H_2O(l)+Sr^(+2)\\OH^-(aq)+CH_3COOH(aq)-->CH_3COO^-(aq)+H_2O(l)`

In which it is seen that the strontium ion is cancelled as it is completely dissociated unlike the acetate at the left side.

Best regards.