Consider the neutralization reaction between CH3COOH and Sr(OH)2. Complete and balance the neutralization reaction, name the products, and write the net ionic equation.

Question

asked Mar 6, 2018 201k views

2 Answers

Katie Byers · Answer 1 · 2018-03-12T05:07:17+0000

Answer:

See the explanation.

Step-by-step explanation:

Hello,

In this case, the overall double displacement undergoing chemical reaction turn out into:

Sr(OH)_2+2CH_3COOH-->(CH_3COO)_2Sr+2H_2O

The names are:

Sr(OH)_2 : strontium hydroxide.

CH_3COOH : acetic acid.

(CH_3COO)_2Sr : strontium acetate.

H_2O : water.

Now, the net ionic equation is obtained from the following procedure:

$Sr^(+2)(aq)+OH^-(aq)+CH_3COOH(aq)-->CH_3COO^-(aq)+H_2O(l)+Sr^(+2)\\OH^-(aq)+CH_3COOH(aq)-->CH_3COO^-(aq)+H_2O(l)$

In which it is seen that the strontium ion is cancelled as it is completely dissociated unlike the acetate at the left side.

Best regards.