Question

Can someone please help

Answer 1

The equation of the line is:

• y = -3/4x + 1

Explanation:

The slope-intercept form of the line equation

`y = mx+b`

where

• m is the slope

• b is the y-intercept

Given the points

• (0, 1)

• (4, -2)

Determining the slope between (0, 1) and (4, -2)

`\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)`

`\left(x_1,\:y_1\right)=\left(0,\:1\right),\:\left(x_2,\:y_2\right)=\left(4,\:-2\right)`

`m=(-2-1)/(4-0)`

Refine

`m=-(3)/(4)`

We know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.

As

The point (0, 1) is given.

It means at x = 0, the vaule of y = 1

Thus, the y-intercept b = 1

now substituting m = -3/4 and b = 1 in the slope-intercept form of line equation

y = mx+b

y = -3/4x + 1

Therefore, the equation of the line is:

• y = -3/4x + 1