Question

Moles of Zn(NO3)2 in 161.50 g of this substance.

Answer 1

Do you know how to break it down?

Answer 2

`0.85 mol Zn(NO_3)_2`

Step-by-step explanation:

we calculate the molecular mass of the compound

`Zn= 65 g/mol\\N= 14 g/mol\\O= 16 g/mol`

`Zn(NO_3)_2= 65+2(14)+ 6(16)=189 g/mol`

We know that in a 1 mol of
`Zn(NO_3)_2` there are 189 grams

To calculate how many moles of
`Zn(NO_3)_2` are in 161.50 grams we apply a simple rule of three

`189g \longrightarrow 1mol\\161.5g \longrightarrow x \\ x=((161.5)(1))/(189)\\ x= 0.85 mol`

`0.85 mol Zn(NO_3)_2`