Question

Factorise the given expressions :
a) (6p2 – 36p + 30) b) (256 − 64y + 4y2
)

Answer 1

a) Factorizing
`6p^2 - 36p + 30` we get
`6(p-5)(p-1)`

b) Factorizing
`4y^2-64y+256` we get
`4(y-8)(y-8)`

Explanation:

Factorise the given expressions :

a)
`6p^2 - 36p + 30`

First we take 6 common:

`6p^2-36p+30\\=6(p^2-6p+5)\\=6(p^2-5p-p+5)\\=6(p(-5)-1(p-5))\\=6(p-5)(p-1)\\`

So, factorizing
`6p^2 - 36p + 30` we get
`6(p-5)(p-1)`

b)
`256 -64y + 4y^2`

Rearranging terms:

`4y^2-64y+256`

Taking 4 common

`4(y^2-16y+64)\\4(y^2-8y-8y+64)\\4(y(y-8)-8(y-8))\\4(y-8)(y-8)`

So, factorizing
`4y^2-64y+256` we get
`4(y-8)(y-8)`