Question

I need to find a formula for R using r for the a) table and the b) table. Any help?

Answer 1

notice the first sequence... notice how you get the next term, whatever the current one is, then you add 2 to it, so.. that's your pattern


`\bf \begin{array}{cccccccc} r=&0&1&2&3&4&5\\ R=&3&5&7&9&11&13\\\\ &--&--&--&--&--&--\\ &&3+2&5+2&7+2&9+2&11+2 \end{array}`

now, let's see the 2nd sequence, notice how you get the current term, by using the current term's ordinal value, square it, then add 1 to it, so, that's the pattern


`\bf \begin{array}{ccccccccll} r=&0&1&2&3&4&5\\ R=&1&2&5&10&17&26\\\\ &--&--&--&--&--&--\\ &0^2+1&1^2+1&2^2+1&3^2+1&4^2+1&5^2+1 \end{array}`

Answer 2

a) R = (r + 3) + r*2

b) R = (r + 1) + (r*2 -1)