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What's the equation of the axis of symmetry of g(x)=x^{2}+4 x+3?A) x=0B) x=-2C) x=2D) x=3

What's the equation of the axis of symmetry of g(x)=x^{2}+4 x+3?A) x=0B) x=-2C) x-example-1
User Jeredriq Demas
by
2.8k points

1 Answer

13 votes
13 votes

Given a quadratic equation of the form:


f(x)=ax^2+bx+c

The equation of the axis of symmetry is obtained using the formula:


x=-(b)/(2a)

From the given quadratic equation:


\begin{gathered} g\mleft(x\mright)=x^2+4x+3 \\ a=1 \\ b=4 \end{gathered}

Therefore, the equation of the axis of symmetry of g(x) is:


\begin{gathered} x=-(4)/(2*1) \\ x=-2 \end{gathered}

The correct option is B.

User Jinowolski
by
3.3k points
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