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A.pex VLS Algebra 1: 6.2.4 Practice - HELP NEEDED!!!

The file below is a picture of the problem I'm stuck on... it's hard to explain. I found Coin A and Coin C, but Coin B is confusing me.
Equations to find the value:
Coin A: V=25(1.07)^t
Coin B: V=40(1.05)^t
Coin C: V=60(1.04)^t
V represents the coin's value and t represents what year it is (kind of).
Please help! Even if you can't do the problem, if you explain how to do it to find Coin B, that would be so appreciated! If you are confused about anything, I'll be happy to explain! Thank you!

A.pex VLS Algebra 1: 6.2.4 Practice - HELP NEEDED!!! The file below is a picture of-example-1

1 Answer

7 votes

Answer:

Answer:1.) I chose coin A and B

2.) Coin: B Value: $40 Annual rate: %5

Coin: A Value: $25 Annual rate: %7

3.) Coin: A P: 25 R: 1.07 Function: v = 25(1.07)^t

Coin: B P: 40 R: 1.05 Function: v = 40(1.05)^t

4.) Base: 1+r Initial: P Exponent: t

If R increased, then P would also increase because you must distribute, and you would be distributing R into P there for if R changes then so would P.

5.) Coin A: Initial value: $25 10 years: $25.70 20 Years: $26.40 30 years: $27.10 60 years: $29.20

Coin B: Initial value: $40 10 years: $40.50 20 years: $41 30 years: $41.50 60 years: $43

Coin C: Initial value: $60 10 years: $60.40 20 years: $60.80 30 years: $61.50 60 years: $62.40

6.) Coin A because the value goes up the most and I probably wouldn't be able to keep the coin for more than 60 years because I would lose it.

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