How many moles are in 68.5 liters of oxygen gas at STP?

asked Jun 5, 2018 218k views

1 vote

by Ahram

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6 votes

68.5 L ( 1 mol O2 / 22.4 L O2 ) = 3.06 mol O2.

So in short your answer is 3.06 mol O2.

I hope this helps. :)

Fifth answered Jun 8, 2018

by Fifth

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