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What is the potential at a distance of 5.0 x 10-10 m from a nucleus of charge 50e? question options:?
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What is the potential at a distance of 5.0 x 10-10 m from a nucleus of charge 50e? question options:?

User Shashan Sooriyahetti
by
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electricpotential V=keQ/r
r = 5.0*10-10 m,
Q = 50e = 50*1.60*10-19
C = 80*10-19 C
V=9.0*109 Nm2C-2* 80*10-19 C / 5.0*10-10

m = 144V

I hope it helped:)
User Satyajit Rout
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