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Calculate the ph of an aqueous solution that is 0.045 m in hcl(aq) at 25°c

User Shvalb
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Remember that HCl is a strong acid will dissociate almost 100%
HCl + H₂O --> H₃O⁺ + Cl⁻

pH = -log[H₃O⁺]
pH = -log(0.045) = 1.35

(The rules for sig figs are that if you take the log of a number with x significant figures, then the result should have x significant decimal places.)

The pH is 1.35
User Indhira
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