Question

What is the volume (in liters) of a 4.2 gram sample of O2 at STP

Answer 1

to solve this we need to use the ideal gas law:

`PV=nRT`

we need to calculate the number of mols of O2

`n=(m)/(Mm)=\frac{4.2g}{32\text{ g/mol}}=0.131mol`

Now we just have to solve for volume and use the number of mols just calculated and the standard pressure (1 atm) and temperature 273.15K:

`V=(nRT)/(P)=\frac{0.131mol\cdot0.082\text{ }(atm\cdot l)/(K\cdot mol)273.15K}{1atm}=2.94l`