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The height of a triangle is two more than three times the base. Determine the dimensions that will give a total area of 28 yards squared. What is the minimum area of such a triangle

User Archbishop
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1 Answer

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h = 3b+2
A = (h*b)/2 28 = (3b+2)b/2 56 = 3b²+2b 0 = 3b² + 2b - 56


\left \{ {{y=2} \atop {x=2}} \right. \int\limits^a_b {x} \, dx \lim_(n \to \infty) a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta \\ \\ \\ x^(2) √(x) \sqrt[n]{x} (x)/(y) x_(123) x^(123) \leq \geq \pi \alpha \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] x_(123) \int\limits^a_b {x} \, dx \left \{ {{y=2} \atop {x=2}}
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User Nerxis
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