Question

PLEAS HELP FAST !!

solve the equation below. please include the steps.

x^2+8x+15=0

Answer 1

(x + 5)(x + 3)
x+5=0, solve it and you get -5.
x+3=0, solve it and you get -3.

The answers are -5 and -3.

Answer 2

`x_(1) =-5\\and \\x_(2) =-3`

Explanation:

Solve by using factoring ------->

rewrite the expresion

x^2+8x+15=0

x^2+5x+3x+15=0

factor out x from the expression

x^2+5x+3x+15=0

xx(x+5)+3x+15=0

xx(x+5)+3(x+5)=0

factor out x+5 from expression

(x+5)x(x+3)=0

when the product of factors equals 0, at least one factor is 0

x+5=0

x+3=0

solve the equation for x

x = -5

x = -3

the equation has 2 solutions

`x_(1) =-5, x_(2) =-3`

Explanation:

Quadratic formula

`x=\frac{-8+\sqrt{8^(2) -4x1x15} }{2x1}`

any expression multiplied by 1 remains the same

`x=\frac{-8+\sqrt{8^(2)-4x15 } }{2}`

evaluate the power

`x=(-8+√(64-4x15) )/(2)`

multiply the numbers

`x=(-8+√(64-60) )/(2)`

subtract the numbers

`x=(8+√(4) )/(2)`

calculate the square root

`x=(-8+2)/(2)`

write solution with a + sign and a - sign

`x=(-8+2)/(2) \\x=(-8-2)/(2)`

calculate the value

`x=-3\\x=-5`

the equation has 2 solutions

`x=-3\\x=-5 \\and\\x_(1) =-5\\x_(2) =-3`