Question

Perimeter of rectangle is 48 inches area is 40 inches what are the length of the side

Answer 1

`\bf \textit{perimeter of a rectangle}=p=side+side+side+side \\\\ or\implies p=w+w+l+l\implies p=2w+2l \\\\ p=2(w+l)\qquad \begin{cases} w=width\\ l=length\\ ------\\ p=48 \end{cases}\implies 40=2(w+l)\\\\ -----------------------------\\\\ \textit{area of it}=A=w\cdot l\qquad \begin{cases} w=width\\ l=length\\ ------\\ A=40 \end{cases}\implies 40=wl\\\\ -----------------------------\\\\`


`\bf thus\qquad \begin{cases} 40=2(w+l)\to (40)/(2)=w+l\to(40)/(2)-l=\boxed{w} \\\\ 40=wl\\ --------------\\ 40=\left( \boxed{(40)/(2)-l} \right)\cdot l \end{cases}`

solve for "l" to find its length