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A 1.00 L volume of HCl reacted completely with 2.00 L of 1.50 M Ca(OH)2 according to the balanced chemical equation below. 2HCl + Ca(OH)2 mc013-1.jpg CaCl2 + 2H2O What was the molarity of the HCl solution?
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A 1.00 L volume of HCl reacted completely with 2.00 L of 1.50 M Ca(OH)2 according to the balanced chemical equation below. 2HCl + Ca(OH)2 mc013-1.jpg CaCl2 + 2H2O What was the molarity of the HCl solution?

User Abdel Aleem
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1 Answer

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Given the balanced chemical equation:

2HCl + Ca(OH)2 ---> CaCl2 + 2H2O

Vhcl = 1 L
Vcaoh2 = 2 L
Ccaoh2 = 1.5mol/L

To solve for the concentration of HCl:

Chcl = ((1.5mol/L * 2L) * (2mol HCl/1 mol Ca(OH)2)) / 1L
= 6 mol/L


User SJC
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