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A bag contains 4 red marbles and 5 blue marbles. What is the probability of randomly selecting a blue marble and then, without replacing it, selecting a red marble? A. 5/18 B.40…
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A bag contains 4 red marbles and 5 blue marbles. What is the probability of randomly selecting a blue marble and then, without replacing it, selecting a red marble? A. 5/18 B.40…
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Jun 1, 2018
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A bag contains 4 red marbles and 5 blue marbles. What is the probability of randomly selecting a blue marble and then, without replacing it, selecting a red marble?
A. 5/18
B.40/81
C.16/81
D.1/6
Help please
Mathematics
high-school
JoshuaTheMiller
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JoshuaTheMiller
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Okay so lets set up our equation...
4 red marbles
5 blue marbles
So the odds are simply
5/9.
If he takes one blue out there is now 4 blues and 4 reds,
So the odds of pulling a red now are
4/8 = 1/2.
All you need to do now is multiply the first 2 ratios together to get the combined odds. (5/9)(1/2) =
5/18
So your answer is 5/18
Hope this helped. Good luck!
Sumit Pandit
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Jun 7, 2018
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Sumit Pandit
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