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A 20-kg child is tossed up into the air by her parent. The child is 2 meters off the ground traveling 5 m/s.

Circle one: KE / GPE / both

Show your work for finding the values of each type of energy the object has

1 Answer

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Data:
m (mass) = 20 Kg
h (height) = 2 m
s (speed) = 5 m/s

K_(E) = ? kinetic energy (Joule)
GPE (Gravitational potential energy ) = ? (joule)
Both = KE + GPE = ?
Adopting: g (gravity) = 10 m/s²

Solving: (Kinetic Energy)

K_(E) = (m*s^2)/(2)

K_(E) = (20*5^2)/(2)

K_(E) = (20*25)/(2)

K_(E) = (500)/(2)

\boxed{K_(E) = 250\:J}\end{array}}\qquad\quad\checkmark

Solving: GPE

GPE = m*g*h

GPE = 20*10*2

\boxed{GPE = 400\:J}\end{array}}\qquad\quad\checkmark

Solving: Both (KE + GPE)

Both = K_(E) + GPE

Both = 250+400

\boxed{Both = 650\:J}\end{array}}\qquad\quad\checkmark



User Hyder
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