Answer:
f'(x) = 6x² + 12x + 5
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
Algebra I
- Terms/Coefficients/Degrees
Calculus
Derivatives
Derivative Notation
Derivative of a constant is 0
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Product Rule:
Explanation:
Step 1: Define
f(x) = (x + 3)(2x² + 5)
Step 2: Differentiate
- Product Rule [Basic Power Rule]: f'(x) = (1 · x¹⁻¹ + 0)(2x² + 5) + (x + 3)(2 · 2x²⁻¹ + 0)
- [Derivative] Simplify: f'(x) = (1)(2x² + 5) + (x + 3)(4x)
- [Derivative] Multiply: f'(x) = 2x² + 5 + (x + 3)(4x)
- [Derivative] Distribute: f'(x) = 2x² + 5 + 4x² + 12x
- [Derivative] Combine like terms: f'(x) = 6x² + 12x + 5