Question

12x^3 - 14^2 - 40x / 2x - 5

Simplify the expression

Answer 1

`\sqrt[n]{x} √(x) √(x) x^(2) \\ \\ \\ \\ \\ \int\limits^a_b {x} \, dx \left \{ {{y=2} \atop {x=2}} \right. x_(123)`

Answer 2

12x^3 - 14x^2 - 40x
-----------------------
2x - 5
(2x-5)(6x^2 +8x)
= -------------------------
2x - 5
=6x^2 + 8x (2x - 5 is canceled out)

answer is C. 6x^2 + 8x

hope that helps