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What is the equation in point-slope form of the line passing through (3, 6) and (−2, 1)? y + 6 = 1(x + 3) y + 1 = −1(x + 2) y − 6 = −1(x + 3) y − 6 = 1(x − 3)
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What is the equation in point-slope form of the line passing through (3, 6) and (−2, 1)? y + 6 = 1(x + 3) y + 1 = −1(x + 2) y − 6 = −1(x + 3) y − 6 = 1(x − 3)
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Sep 14, 2018
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What is the equation in point-slope form of the line passing through (3, 6) and (−2, 1)?
y + 6 = 1(x + 3)
y + 1 = −1(x + 2)
y − 6 = −1(x + 3)
y − 6 = 1(x − 3)
Mathematics
high-school
Miguel Costa
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Miguel Costa
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Find the slope first.
So
slope (m) = y2-y1/x2-x1
m=1-6/-2-3
m=-5/-5
m=1
The slope is 1
The equation for point slope form is
y-y1=m(x-x1)
y-6=1(x-3)
Therefore the equation in point slope form of the line passing through the points is y-6=1(x-3)
Zain Shaikh
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Sep 16, 2018
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Zain Shaikh
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(3,6)(-2,1)
slope = (1 - 6) / (-2 - 3) = -5/-5 = 1
point slope form : y - y1 = m(x - x1)
slope(m) = 1
(3,6)....x1 = 3 and y1 = 6
now we sub
y - 6 = 1(x - 3) <===
Lvarayut
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Sep 20, 2018
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Lvarayut
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