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If f'(x)=tan^-1(x^3-x) at how many points is the tangent line to the graph of y=f(x) parallel to the line y=2x

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The slope of the line
y=2x is 2, and any parallel line will have the same slope. Since
f'(x_0) gives the tangent line to
y=f(x) at
x=x_0, any tangent line will be parallel whenever


\arctan(x^3-x)=2

But this never happens, since
|\arctan x|\le\frac\pi2<2

So there will never be a tangent line with slope 2, and thus no tangent line parallel to
y=2x.
User Dpedoneze
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