Find the value of the expression 2x3 + 3y2 − 17 when x = 3 and y = 4.

asked Jan 23, 2018 209k views

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2x^3 + 3y^2 − 17
Plug the value of the x and y
2(3)^3+3(4)^2-17
3^3=27
4^2=16
=2(27)+3(16)-17
=54+48-17
=102-17
=85

Nathan Tew answered Jan 28, 2018

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