145k views
5 votes
How many possible combination outcomes consist of two heads when you toss a fair coin four times?

1 Answer

6 votes

\dbinom42=(4!)/(2!(4-2)!)=(4*3*2*1)/(2*1*2*1)=3*2=6
User Sarson
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.