I inserted a picture of the question, could you please take the short way.

Petr Krampl asked Jan 6, 2023

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Petr Krampl asked Jan 6, 2023

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11 votes

Recall the following property of exponents:

$(a\cdot b)^x=a^x\cdot b^x\text{.}$

Therefore:

$(14\cdot(-58))^(16)=14^(16)\cdot(-58)^(16)\text{.}$

Answer: Option A.

Andy Jazz answered Jan 12, 2023

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