Solve the following quadratic equation using the quadratic formula. Which of the following expressions gives the numerators of the solutions? 10x^2 - 19x + 6 = 0

Question

asked Sep 5, 2018 144k views

2 Answers

Donnikitos · Answer 1 · 2018-09-11T20:39:25+0000

I hope the choices for the numerators of the solutions are given.

I am showing the complete work to find the solutions of this equation , it will help you to find an answer of your question based on this solution.

The standard form of a quadratic equation is :

ax² + bx + c = 0

And the quadratic formula is:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

So, first step is to compare the given equation with the above equation to get the value of a, b and c.

So, a = 10, b = -19 and c = 6.

Next step is to plug in these values in the above formula. Therefore,

$x=((-19)-\pm√((-19)^2-4*10*6))/(2*10)$

$=(19\pm√(361-240))/(20)$

$=(19\pm√(121))/(20)$

$=(19\pm11)/(20)$

So,
x=(19-11)/(20) ,(19+11)/(20)

x=(8)/(20) , (30)/(20)

So,
x= (2)/(5) ,(3)/(2)

Hope this helps you!