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How many grams of aluminum sulfide would form if 2.25 liters of a 1.50 molar aluminum chloride solution reacts with 2.00 liters of a 2.75 molar hydrosulfuric acid (H2S) solution? 2AlCl3 + 3H2S yields Al2S3 + 6HCl

a.18.6 g
b.101 g
c.253 g
d.275 g

User Nery Jr
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How many grams of aluminum sulfide would form if 2.25 liters of a 1.50 molar aluminum-example-1
User Jproffitt
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