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What are the limiting and excess reactants when 3.22 moles of Al react with 6.96 moles of HBr

What are the limiting and excess reactants when 3.22 moles of Al react with 6.96 moles-example-1
User Pictoru
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1 Answer

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18 votes

Answer

HBr is the limiting reactant

Al is the excess reactant.

Step-by-step explanation

Given:

Moles of Al = 3.22 mol

Moles of HBr = 6.96 mol

Equation: 2 Al + 6 HBr → 2 AlBr₃ + 3 H₂

What to find;

The limiting and excess reactants.

Solution:

Note: The limiting reactant is the reactant that is completely used up in a reaction, and thus determines when the reaction stops. While the excess reactant is the opposite.

From the given balanced chemical equation;

2 moles of Al require 6 moles of HBr

Therefore, the given 3.22 moles of Al will require (3.22/2) x 6 = 9.66 moles of HBr

Since the given moles of HBr is 6.96 mol not up to 9.66 moles required, then HBr is the limiting reactant and Al is the excess reactant.

HBr is the limiting reactant

Al is the excess reactant.

User SimonBiggs
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