Answer
HBr is the limiting reactant
Al is the excess reactant.
Step-by-step explanation
Given:
Moles of Al = 3.22 mol
Moles of HBr = 6.96 mol
Equation: 2 Al + 6 HBr → 2 AlBr₃ + 3 H₂
What to find;
The limiting and excess reactants.
Solution:
Note: The limiting reactant is the reactant that is completely used up in a reaction, and thus determines when the reaction stops. While the excess reactant is the opposite.
From the given balanced chemical equation;
2 moles of Al require 6 moles of HBr
Therefore, the given 3.22 moles of Al will require (3.22/2) x 6 = 9.66 moles of HBr
Since the given moles of HBr is 6.96 mol not up to 9.66 moles required, then HBr is the limiting reactant and Al is the excess reactant.
HBr is the limiting reactant
Al is the excess reactant.