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a box contains 29 widgets, 4 of which are defective. if 4 are sold at random, find the probability that (a) all are defective (b) none are defective

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The probability that all 4 widgets sold are defective is 0.00036, and the probability that none of the 4 widgets sold are defective is 0.55229.

How to find probability?

a) Probability that all are defective

There are 4 defective widgets and 25 non-defective widgets. If 4 widgets are sold at random, the probability that all of them are defective is:

P(all defective) = (4/29)(3/28)(2/27)(1/26)

= 0.00036

b) Probability that none are defective

There are 25 non-defective widgets and 4 defective widgets. If 4 widgets are sold at random, the probability that none of them are defective is:

P(none defective) = (25/29)(24/28)(23/27)(22/26)

= 0.55229

Therefore, the probability that all 4 widgets sold are defective is 0.00036, and the probability that none of the 4 widgets sold are defective is 0.55229.

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