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What are the solutions to 4(x+5)^2=4?

User DWR
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First, simplify both sides of the equation: 4x^2 + 40x + 100 = 4. Then, subtract 4 from both sides: 4x^2 + 40x + 96 = 0. Now, you can factor the left side of the equation: 4(x + 4)(x + 6) = 0. You can now set factors to 0, which will leave you x + 4 = 0 and x + 6 = 0. To find x, simply subtract 4 and 6 from both sides. You answer would be x = -4 and x = -6.
User Peuge
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(X+5)²=4/4
X+5=1, X+5=-1
X=1-5 X=-1-5
X=-4 X=-6
User Kenneth Clark
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