Question

Use the discriminant and select whether the roots of 4x 2 - 3x + 3 = 0 are real or imaginary.

Answer 1

to find the discriminant we use b^2 - 4ac

equation of 4x^2 - 3x + 3 = 0
a b c

-3^2 - 4 (4)(3) = -39
if b^2 - 4ac < 0, there are 2 complex roots or...no real roots...in this case imaginary.

Answer 2

roots are imaginary

Explanation:

`4x^2 - 3x + 3 = 0`

Formula to find discriminant is
`b^2-4ac`

Given equation is in the form of ax^2+bx+c=0

a=4, b=-3, c=3

Plug in all the values in the discriminant formula

`b^2-4ac=(-3)^2-4(4)(3)=-39`

When discriminant >0, the roots are real

when discriminant <0 then roots are imaginary

we got discriminant =-39 that is less than 0, so roots are imaginary