Question

How many moles of nitrogen are formed when 58.6 g of KNO3 decomposes according to the following reaction? The molar mass of KNO3 is 101.11 g/mol.

4 KNO3(s) → 2 K2O(s) + 2 N2(g) + 5 O2(g)

Answer 1

Hope this helps you!

Answer 2

Answer:0.28975 moles of nitrogen are formed .

Step-by-step explanation:

`4KNO_3(s)\rightarrow 2K_2O(s)+2N_2(g)+5O_2(g)`

Number of moles of
`KNO_3=\frac{\text{Mass of the}KNO_3}{\text{Molar mass of the}KNO_3}=(58.6 g)/(101.11 g/mol)=0.5795 moles`

According to reaction , 4 mol of
`KNO_3` produces 2 moles of
`N_2` gas.

Then,0.5795 moles of
`KNO_3` will produce=
`(2)/(4)* 0.5795` moles of
`N_2` gas:

`(2)/(4)* 0.5795=0.28975 moles`

0.28975 moles of nitrogen are formed.