Question

What are the zeros of (x)= (3x - 1)(2x + 5) (7x-14) ^2

Answer 1

I use my calculator ( TI-84 Plus CE-T)
Y1 (the blue one) = (3x-1)(2x+5)(7x-14)^2
Graph
You have 2 zeros
2nd trace zero
The first one gives x= 1/3 and y = 0
(1/3,0)
The second one gives x= 2 and y= 0
(2,0)