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4 votes
Given right triangle DEF, what is the value of tan(F)?

2 Answers

2 votes

Answer:
(40)/(9)

Explanation:

We know that for any angle x in a triangle ,


\tan x=\frac{\text{side opposite to x}}{\text{side adjacent to x}}

Now, for the given triangle DEF, the value of tan(F) is given by :-


\tan F=\frac{\text{side opposite to F}}{\text{side adjacent to F}}\\\\\Rightarrow\ \tan F=(40)/(9)

Hence, the value of tan(F) =
=(40)/(9)

User Max Shifrin
by
7.5k points
2 votes

we know that

In the right triangle DEF

the tangent of the angle F is equal to


tan(F)=(opposite\ side\ angle\ F)/(adjacent\ side\ angle\ F)=(DE)/(EF)

substitute the values


tan(F)=(40)/(9)

therefore

the answer is the option


(40)/(9)

User Yetimwork Beyene
by
8.0k points

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