Question

How many oxygen molecules are present in 113.97 liters of oxygen gas at STP?

Answer 1

1 mole of any gas occupies a volume of 22.4L, therefore there are 3.022×10^24 molecules of oxygen gas in 113.97 L

Answer 2

Answer:
`30.64* 10^(23)molecules`

Step-by-step explanation: According to Avogadro's law, 1 mole of every substance occupies 22.4 Liters at standard temperature and pressure and contains avogadro's number
`(6.023* 10^(23))` of particles.

22.4 L of oxygen gas
`(O_2)` contains =
`6.023* 10^(23)` molecules of oxygen

113.97 L of oxygen gas
`(O_2)` contains =
`(6.023* 10^(23))/(22.4L)* 113.97L=30.64* 10^(23)`molecules of oxygen