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Cos b + sin b × tan b = sec b

User IzumiSy
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1 Answer

4 votes
cosb+sinb*tanb=secb

take LHS first
cosb+sinb*sinb/cosb----------tanb=sinb/cosb
cosb+(sinb)^2/cosb
[cos^2b+sin^2b]/cosb
1/cosb=secb -------------- cos^2b+sin^2b=1
LHS=RHS
User Jupiteror
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