Question

I. Let f(x) = 2x – 1, g(x) = 3x, and h(x) = x2

+ 1. Compute the following:

1. f(g(-1))
2. f o h(3)
3. g(f(-5))
4. h(f(x))
5. f(f(x)) 6
. h o g(x)

Answer 1

f(h(3))
h(3) = 3^2 + 1 = 9 + 1 = 10
f(10) = 2(10) - 1 = 19

g(f(-5))
f(-5) = 2(-5) -1 = -10 - 1 = -11
g(-11) = 3(-11) = -33

f(f(6))
f(6) = 2(6) - 1 = 12 - 1 = 11
f(11) = 2(11) - 1 = 21

I think I already did the others on a separate question.