Question

The volume of an ideal gas is decreased from 5.0 l to 5.0 ml at a constant pressure of 2.0 atm. calculate the work associated with this process

Answer 1

5 ml = 0,05l
Work = Pressure * (Volume difference)
W= 2 * (V2 - V1)
W= 2 * (4,95)

Answer 2

The work is 9.99J.

Step-by-step explanation:

The work associated with a process is given by the following formula:

`W = P*\Delta`

In which W is the work, P is the pressure and
`\Delta` is the difference of volume.

In this problem, we have that:

The volume of an ideal gas is decreased from 5.0 l to 5.0 ml. Each ml has 0.001l. So the volume of the ideal gas is decreased from 5.0l to 0.005l. So

`\Delta = 4.995`.

Constant pressure of 2.0 atm. So
`P = 2`.

`W = P*\Delta`

`W = 2*4.995`

`W = 9.99`

The work is 9.99J.