Answer:
It's CNBD. Leave the first blank...well blank
In the situation where segment is perpendicular to segment , such that is the perpendicular bisector to segment we have the following two column proof;
Statement Reason
M is the midpoint of Given
≅ Definition of midpoint
≅ Reflexive property
∠CMA = ∠IMA = 90° Definition of perpendicular bisector
ΔCAM ≅ ΔIAM By the Side-Angle-Side (SAS) rule of congruency
However, where the segment is not be assumed as perpendicular to segment , then CNBD
Explanation:
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