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Line / contains the points (-4, -1) and (1, 1) asshown below.432-10x-212-1P-2--3-Line m will be drawn perpendicular to line I andcontaining point P. Identify the coordinates ofanother point on line m.(-1, 4)O (1,3)(-2,-4)(5,3)

Line / contains the points (-4, -1) and (1, 1) asshown below.432-10x-212-1P-2--3-Line-example-1
User Nodebase
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1 Answer

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Let's begin by listing out the information given to us:

Line m is perpendicular to line P

Line P: (x, y) = (-4, -1), (1, 1)

We will proceed to calculate for the slope of the line P (as shown below):

Slope (m) = Δy/Δx

Slope (m) = (1 - - 1)/(1 - - 4) = 2/5

Slope (m) = 2/5

The slope of a parallel line is the negative reciprocal of the slope of the line.

Line m: slope (m) = -1/(2/5) = -5/2

Line m: slope (m) = -5/2

We calculate for the equation of the line using the point-slope equation. We have

y - y1 = m(x - x1) ⇒

(x1, y1) = (1, 1)

y - 1 = 2/5 (x - 1) ⇒ y - 1 = 2/5x - 2/5

y = 2/5x - 2/5 + 1

y = 2/5x + 3/5

We will proceed to put the value of the new slope into the equation. We have:

y = -5/2x + b ; (x, y) = (1, 1) ⇒ 1 = -5/2(1) + b

⇒ b = 5/2

Substitute the value of b into the point-slope equation, and we obtain the equation of line m. We have:

y = -5/2x + 5/2

User Harshit Rathi
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