Question

find three consecutive natural numbers such that the difference of 5 times the third number and four times the first number is twice the second number

Answer 1

theya re 1 apart
n,n+1,n+2

difference of 5 times (n+2) and 4 times n is 2 times (n+1)

5(n+2)-4n=2(n+1)
distribute
5n+10-4n=2n+2
n+10=2n+2
minus n both sides
10=n+2
minus 2 both sides
8=n
n+1=9
n+2=10

th enumbers are 8,9,10