Question

Find the area of a regular hexagon with the given measurement. 4-inch side A = sq. in. Please show work.

Answer 1

The area of hexagon is 41.57 inch².

Explanation:

The formula for area of regular hexagon is

`A=(3√(3))/(4)a^2`

Where, a is the side length of regular hexagon.

It is given that the length of side is 4 inch.

The area of regular hexagon is

`A=(3√(3))/(4)*(4)^2`

`A=(3√(3))/(2)* 16`

`A=3√(3)* 8`

`A=24√(3)`

`A=41.57`

Therefore the area of hexagon is 41.57 inch².

Answer 2

`A=41.58(inches)^2`

Explanation:

Given: The side of the regular hexagon measures 4 inches.

To find: The area of the regular hexagon.

Solution: The area of the regular hexagon can be found as:

`A=(3√(3))/(2)(side)^2`

`A=(3√(3))/(2)(4)^2`

`A=(3√(3))/(2)(16)`

`A=24√(3)`

`A=41.58(inches)^2`

Thus, the area of the regular hexagon will be equal to
`41.58 (inches)^2`.