Question

Given a triangle ABC at points A = ( - 2, 2 ) B = ( 2, 5 ) C = ( 2, 0 ), and a first transformation of right 4 and up 3, and a second transformation of left 2 and down 5, what would be the location of the final point B'' ?

Answer 1

Answer: The answer would be (4,3)

Step-by-step explanation: because if you started with (2,5), which would be (x,y) x goes left and right, and y goes up and down, and the questions says that you have to go 4 to the right and 3 up, then add 4 to 2, which is 6, and 3 to 5, which is 8, so now you have the point (6,8), then the second translation would be 2 to the left, and down 5, this is negative so you subtract this time, so subtract 2 from 6, which is 4, and 5 from 8, which is 3, so your final answer is (4,3).

Answer 2

a. (4, 3)

Explanation

The translation of a point (x, y) a units to the right and b units up transforms the point into (x + a, y + b).

Considering point B(2, 5), translating it 4 units to the right and 3 units up, we get:

B(2, 5) → (2+4, 5+3) → B'(6, 8)

The translation of a point (x, y) c units to the left and d units down transforms the point into (x - c, y - d).

Considering point B'(6, 8), translating it 2 units to the left and 5 units down, we get:

B'(6, 8) → (6 - 2, 8 - 5) → B''(4, 3)