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What is the line of symmetry for the parabola whose equation is y = -x^2 + x + 3?

User Hervey
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2 Answers

1 vote
in the form y=ax^2+bx+c
the axis of symmetry is x=-b/2a

so

y=-1x^2+1x+3
b=1
a=-1

line of symmetry is x=-1/(2*-1)=-1/-2=1/2

the axis of symmetry is x=1/2
User ScottLenart
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4 votes
THE PARABOLA OPENS DOWN (WHICH IS MAXIMUM ) AND X=1/2
User Corina
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