Question

3. When a fo.0-g nugget of pure gold is heated from 49°C to 60.0°C, it absorbed 5339.01 of energy. What is

the specific heat of gold?

Answer 1

Complete Question:

When a 40.0-g nugget of pure gold is heated from 49°C to 60.0°C, it absorbed 5339.01 of energy. What is

the specific heat of gold?

Answer:

Specific heat capacity, c = 12.134J/KgC

Step-by-step explanation:

Given the following data;

Mass = 40g

Initial temperature, T1 = 49°C

Final temperature, T2 = 60.0°C

Quantity of heat = 5339.01J

To find the specific heat capacity of gold;

Heat capacity is given by the formula;

`Q = mcdt`

Where;

• Q represents the heat capacity or quantity of heat.

• m represents the mass of an object.

• c represents the specific heat capacity of water.

• dt represents the change in temperature.

dt = T2 - T1

dt = 60 - 49

dt = 11°C

Substituting the values into the equation, we have;

`5339.01 = 40*c*11`

`5339.01 = 440c`

`c = \frac {5339.01}{440}`

Specific heat capacity, c = 12.134J/KgC