Question

Write the standard form of the equation of the circle described below

Answer 1

Given:

Center ( 8, -4)

Radius (r) = 3

Find-:

Standard equation of a circle

Explanation-:

The standard equation of a circle:

`(x-h)^2+(y-k)^2=r^2`

Where,

`\begin{gathered} (h,k)=\text{ Center} \\ \\ r=\text{ Radius} \end{gathered}`

So equation of circle is:

`\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ \\ (h,k)=(8,-4) \\ \\ r=3 \end{gathered}`
`\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ \\ (x-8)^2+(y-(-4))^2=3^2 \\ \\ (x-8)^2+(y+4)^2=9 \end{gathered}`