Question

Find area and perimeter of the shape identify the shape

Answer 1

Part A

The dimensions of the shape shown are given as

length, l = 12 in

breadth (b) = width, w = 4 in

The area of the shape is given as;

`\begin{gathered} A=l* b \\ A=12*4 \\ A=48in^2 \end{gathered}`

Therefore, the area of the shape is 48 square inches.

Part B

The perimeter of a shape is the sum of all the outer sides enclosing the shape

From the above shape, we add all four sides together

`\begin{gathered} P=12+12+4+4 \\ P=32in \end{gathered}`

Consequently, we can get the perimeter using formula method as well

`\begin{gathered} P=2(l+b) \\ P=2(12+4) \\ P=2(16) \\ P=2*16 \\ P=32in \end{gathered}`

Therefore, the perimeter of the shape is 32 inches.

Part C

From the dimension given in the question, since the shape has a length and width, and the length and width are not equal, then the shape is a rectangle.

The shape, therefore, is a rectangle.