83.9k views
2 votes
Solve the following quadratic equation using the quadratic formula and then choose the correct solution set.

8x2 - 6x + 1 = 0

{1/8,5/8 }
{1/4, 1/2}
{±1/2}

User GeckoTang
by
9.3k points

2 Answers

0 votes
8x2 - 6x + 1 = 0
(2x-1)(4x-1) = 0

2x-1 = 0
x=1/2

4x-1=0
x = 1/4

answer {1/4, 1/2}(second choice)
User Guli
by
8.0k points
1 vote

Answer: The the correct solution set is (B)
\{(1)/(4),(1)/(2)\}.

Step-by-step explanation: The given equation is


8x^2-6x+1=0.~~~~~~~~~~~~~~(i)

We are to choose the correct solution set after solving the above equation by using quadratic formula.

We know that, the solution set for the quadratic equation
ax^2+bx+c=0,~a\\eq 0 is given by


x=(-b\pm √(b^2-4ac))/(2a).

In the given equation (i), we have


a=8,~~b=-6,~~c=1.

Therefore, the solution set will be given by


x=(-b\pm √(b^2-4ac))/(2a)\\\\\\\Rightarrow x=(-(-6)\pm √((-6)^2-4* 8* 1))/(2* 8)\\\\\\\Rightarrow x=(6\pm√(36-32))/(16)\\\\\\\Rightarrow x=(6\pm√(4))/(16)\\\\\\\Rightarrow x=(6\pm 2)/(16)\\\\\\\Rightarrow x=(6+2)/(16),~~(6-2)/(16)\\\\\\\Rightarrow x=(8)/(16),~~(4)/(16)\\\\\\\Rightarrow x=(1)/(2),~~(1)/(4).

Thus, the correct solution set is (B)
\{(1)/(4),(1)/(2)\}.

User Jsv
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories