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Solve the following quadratic equation using the quadratic formula and then choose the correct solution set.

8x2 - 6x + 1 = 0

{1/8,5/8 }
{1/4, 1/2}
{±1/2}

User GeckoTang
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2 Answers

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8x2 - 6x + 1 = 0
(2x-1)(4x-1) = 0

2x-1 = 0
x=1/2

4x-1=0
x = 1/4

answer {1/4, 1/2}(second choice)
User Guli
by
6.6k points
1 vote

Answer: The the correct solution set is (B)
\{(1)/(4),(1)/(2)\}.

Step-by-step explanation: The given equation is


8x^2-6x+1=0.~~~~~~~~~~~~~~(i)

We are to choose the correct solution set after solving the above equation by using quadratic formula.

We know that, the solution set for the quadratic equation
ax^2+bx+c=0,~a\\eq 0 is given by


x=(-b\pm √(b^2-4ac))/(2a).

In the given equation (i), we have


a=8,~~b=-6,~~c=1.

Therefore, the solution set will be given by


x=(-b\pm √(b^2-4ac))/(2a)\\\\\\\Rightarrow x=(-(-6)\pm √((-6)^2-4* 8* 1))/(2* 8)\\\\\\\Rightarrow x=(6\pm√(36-32))/(16)\\\\\\\Rightarrow x=(6\pm√(4))/(16)\\\\\\\Rightarrow x=(6\pm 2)/(16)\\\\\\\Rightarrow x=(6+2)/(16),~~(6-2)/(16)\\\\\\\Rightarrow x=(8)/(16),~~(4)/(16)\\\\\\\Rightarrow x=(1)/(2),~~(1)/(4).

Thus, the correct solution set is (B)
\{(1)/(4),(1)/(2)\}.

User Jsv
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7.0k points