Question

Evaluate g(-3)Determine the coordinates of the point given by the answer aboveEvaluate g(2a)Step By Step Explanation Please

Answer 1

Given the quadratic equation:

`g(x)=3x^2-5x+4`

Let's solve for the following:

• (a) g(-3)

To solve for g(-3), substitute -3 for x and evaluate.

Thus, we have:

`\begin{gathered} g(x)=3x^2-5x+4 \\ \\ g(-3)=3(-3)^2-5(-3)+4 \\ \\ g(-3)=3(9)+15+4 \\ \\ g(-3)=27+15+4 \\ \\ g(-3)=46 \end{gathered}`

Hence, we have:

g(-3) = 46

• (b) To determine the coordinates of the point given in question (a).

In the function, g(x) can also be written as y.

Thus, from g(-3), we have the following:

x = -3

y = 46

When x = -3, the value of y = 46

In point form, we have the coordinates:

(x, y) ==> (-3, 46)

Therefore, the coordinates of the given point by the answer in (a) is:

(-3, 46)

• (c) Evaluate g(2a).

To evaluate g(2a), substitute 2a for x in the equation and evaluate.

Thus, we have:

`\begin{gathered} g(x)=3x^2-5x+4 \\ \\ g(2a)=3(2a)^2-5(2a)+4 \\ \\ g(2a)=3(4a^2)-5(2a)+4 \\ \\ g(2a)=12a^2-10a+4 \end{gathered}`

ANSWERS:

• (a) g(-3) = 46

• (b) (-3, 46)

• (c) g(2a) = 12a² - 10a + 4